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4x^2-54x+140=0
a = 4; b = -54; c = +140;
Δ = b2-4ac
Δ = -542-4·4·140
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-26}{2*4}=\frac{28}{8} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+26}{2*4}=\frac{80}{8} =10 $
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